关于java:java-替换docx文件中的字符串

替换 docx 文件外面的 ${} 字符串

public class Main {public static void main(String[] args) throws Exception {
        String template = "C:\\Users\\lzh\\Desktop\\ 模板.docx";
        String outSrc = "C:\\Users\\lzh\\Desktop\\ 简历.docx";

        var is = new FileInputStream(template);
        var os = new FileOutputStream(outSrc);

        editDocx(os, is, xml -> {Map<String,String> map = new HashMap<>();
            map.put("${name}", "李 **");
            map.put("${sex}", "男");
            map.put("${age}", "21");

            Pattern p = Pattern.compile("(\\$\\{)([\\w]+)(\\})");
            Matcher m = p.matcher(xml);
            StringBuffer sb = new StringBuffer();
            while (m.find()) {String group = m.group();
                m.appendReplacement(sb, map.get(group));
            }
            m.appendTail(sb);
            xml = sb.toString();

            return xml;
        });
    }

    public static void editDocx(OutputStream bos,InputStream is, Process process){ZipInputStream zin = new ZipInputStream(is);
        ZipOutputStream zos = new ZipOutputStream(bos);
        try {
            ZipEntry entry;
            while((entry = zin.getNextEntry()) != null) {
                // 把输出流的文件传到输入流中 如果是 word/document.xml 由咱们输出
                zos.putNextEntry(new ZipEntry(entry.getName()));
                if("word/document.xml".equals(entry.getName())){String xml = new BufferedReader(new InputStreamReader(zin)).lines().collect(Collectors.joining(System.lineSeparator()));
                    xml = process.process(xml);

                    ByteArrayInputStream byteIn = new ByteArrayInputStream(xml.getBytes());
                    int c;
                    while ((c = byteIn.read()) != -1) {zos.write(c);
                    }
                    byteIn.close();}else {
                    int c;
                    while ((c = zin.read()) != -1) {zos.write(c);
                    }
                }
            }
        } catch (IOException e) {e.printStackTrace();
        } finally {
            try {zos.close();
                zin.closeEntry();
                zin.close();} catch (IOException e) {e.printStackTrace();
            }
        }
    }
}

interface Process {String process(String xml);
}