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数据结构—二叉排序树(Java)
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阐明
二叉排序树:BST: (Binary Sort(Search) Tree), 对于二叉排序树的任何一个非叶子节点,要求左子节点的值比以后节点的值小,右子节点的值比以后节点的值大
代码
package cn.guizimo.binarysorttree;
public class BinarySortTree {public static void main(String[] args) {int[] arr = {7, 3, 10, 12, 5, 1, 9, 2};
BinarySortTreeDemo binarySortTree = new BinarySortTreeDemo();
for(int i = 0; i< arr.length; i++) {binarySortTree.add(new Node(arr[i]));
}
System.out.println("中序遍历");
binarySortTree.infixOrder(); // 1, 3, 5, 7, 9, 10, 12
binarySortTree.delNode(12);
System.out.println("以后根节点 root=" + binarySortTree.getRoot());
System.out.println("删除后中序遍历");
binarySortTree.infixOrder();}
}
class BinarySortTreeDemo {
private Node root;
public Node getRoot() {return root;}
// 查找以后节点
public Node search(int value) {if (root == null) {return null;} else {return root.search(value);
}
}
// 找到最小值
public int delRightTreeMin(Node node) {
Node target = node;
while(target.left != null) {target = target.left;}
delNode(target.value);
return target.value;
}
// 删除节点
public void delNode(int value) {if (root == null) {return;} else {
// 删除叶子节点
Node targetNode = search(value);
if (targetNode == null) {return;}
if (root.left == null && root.right == null) {
root = null;
return;
}
Node parent = searchParent(value);
if (targetNode.left == null && targetNode.right == null) {if (parent.left != null && parent.left.value == value) {parent.left = null;} else if (parent.right != null && parent.right.value == value) {parent.right = null;}
// 删除两颗子树的节点
} else if (targetNode.left != null && targetNode.right != null) {int i = delRightTreeMin(targetNode.right);
targetNode.value = i;
// 删除一颗子树的节点
} else {if (targetNode.left != null) {if (parent != null) {if (parent.left.value == value) {parent.left = targetNode.left;} else {parent.right = targetNode.right;}
} else {root = targetNode.left;}
} else {if (parent != null) {if (parent.left.value == value) {parent.left = targetNode.right;} else if (parent.right.value == value) {parent.right = targetNode.right;}
} else {root = targetNode.right;}
}
}
}
}
// 查问以后节点的父节点
public Node searchParent(int value) {if (root == null) {return null;} else {return root.searchParent(value);
}
}
// 增加节点
public void add(Node node) {if (root == null) {root = node;} else {root.add(node);
}
}
// 中序遍历
public void infixOrder() {if (root != null) {root.infixOrder();
} else {System.out.println("");
}
}
}
class Node {
int value;
Node left;
Node right;
public Node(int value) {this.value = value;}
@Override
public String toString() {
return "Node{" +
"value=" + value +
'}';
}
// 查找节点
public Node search(int value) {if (value == this.value) {return this;} else if (value < this.value) {if (this.left == null) {return null;}
return this.left.search(value);
} else {if (this.right == null) {return null;}
return this.right.search(value);
}
}
// 查问父节点
public Node searchParent(int value) {if ((this.left != null && this.left.value == value) ||
(this.right != null && this.right.value == value)) {return this;} else {if (value < this.value && this.left != null) {return this.left.searchParent(value);
} else if (value >= this.value && this.right != null) {return this.right.searchParent(value);
} else {return null;}
}
}
// 增加节点
public void add(Node node) {if (node == null) {return;}
if (node.value < this.value) {if (this.left == null) {this.left = node;} else {this.left.add(node);
}
} else {if (this.right == null) {this.right = node;} else {this.right.add(node);
}
}
}
// 中序遍历
public void infixOrder() {if (this.left != null) {this.left.infixOrder();
}
System.out.println(this);
if (this.right != null) {this.right.infixOrder();
}
}
}
测试
感激
尚硅谷
以及勤奋的本人
正文完