关于java:代码-石头剪刀布石头剪刀布

问题形容

Alice, Bob 和 Cindy 一起玩猜拳的游戏。和两个人的猜拳相似, 每一轮, 他们会从石头、剪刀、布中各自选一个出拳, 根本的输赢规定是石头赢剪刀、剪刀赢布、布赢石头。 如果一轮中正好能够分成输赢两边, 则负边的每个人要领取给胜边的每个人一块钱。如果无奈分成输赢两边, 则都不出钱 。比方, 如果 Alice 出石头, 而 Bob 和 Cindy 都出布, 则 Alice 要分领取 Bob 和 Cindy 一块钱。再如, 如果 Alice 出石头, Bob 出剪刀, Cindy 出布, 则都不出钱。他们三人共进行了 n 轮游戏, 请问最初每个人净赚多少钱? 即赚的钱减去领取的钱是多少?

代码

package Ring1270.pra.java01;
import java.util.Scanner;
/**
 * finger-guessing game: *  n:number of games *  A: Person A's money *  B: Person B's money *  C: Person C's money *  0: Stand for stone *  1: Stand for Scissor *  2: Stand for cloth *  rule1: Two persons give the same result means game over *  Rule2: The money add 1 everytime which win *  Rule3:The money less 1 everytime which fail * */public class D_FingerGuessingGame {public static void main(String[] args) {
        int A = 0;
        int B = 0;
        int C = 0;
        Scanner scanner = new Scanner(System.in);
        System.out.printf("The number of game:");
        int n = scanner.nextInt();
        StringBuffer stringBuffer = new StringBuffer();
        for (int i = 0; i <= n; i++) {String s = scanner.nextLine();
            char[] D = s.toCharArray();
            for (int j = 0; j < D.length; j++) {
                //A and B success
 if (D[0] == D[1] && D[0] != D[2]) {if ('0' == D[0] && '1' == D[2]) {
                        A++;
                        B++;
                        C -= 2;
                    }
                    else if ('1' == D[0] && '2' == D[2]) {
                        A++;
                        B++;
                        C -= 2;
                    }
                    else if ('2' == D[0] && '0' == D[2]) {
                        A++;
                        B++;
                        C -= 2;
                    }else {
                        A--;
                        B--;
                        C += 2;
                    }
                }
                // A and C success
 if (D[0] == D[2] && D[0] != D[1]) {if ('0' == D[0] && '1' == D[1]) {
                        A++;
                        B -= 2;
                        C++;
                    }
                    else if ('1' == D[0] && '2' == D[1]) {
                        A++;
                        B -= 2;
                        C++;
                    }
                    else if ('2' == D[0] && '0' == D[1]) {
                        A++;
                        B -= 2;
                        C++;
                    }else {
                        A--;
                        B += 2;
                        C--;
                    }
                }
                // C and B success
 if (D[1] == D[2] && D[1] != D[0]) {if ('0' == D[1] && '1' == D[0]) {
                        A -= 2;
                        B++;
                        C++;
                    }
                    else if ('1' == D[1] && '2' == D[0]) {
                        A -= 2;
                        B++;
                        C++;
                    }
                    else if ('2' == D[1] && '0' == D[0]) {
                        A -= 2;
                        B++;
                        C++;
                    }
                    else {
                        A += 2;
                        B--;
                        C--;
                    }
                }
                break;
            }
        }
        System.out.println(A);
        System.out.println(B);
        System.out.println(C);
    }
}

运行截图