关于elasticsearch:扩展Elasticsearch客户端简化ES查询net-coreframework

Elasticsearch .net 客户端提供了两种形式进行查问操作

基于对象结构查问

new IdsQuery
{
    Name = "named_query",
    Boost = 1.1,
    Values = new List<Id> {1, 2, 3, 4},
}

基于 lambda 语法查问

q
.Ids(c => c
    .Name("named_query")
    .Boost(1.1)
    .Values(1, 2, 3, 4)
)

两种形式各有优缺点，最次要起因是条件稍有点简单后，感觉像在套娃，一层套一层，特地是 lambda

如：

var searchResults = this.Client.Search<Project>(s => s
    .Query(q => q
        .Bool(b => b
            .Should(bs => bs.Term(p => p.Name, "x"),
                bs => bs.Term(p => p.Name, "y")
            )
        )
    )
);

官网文档有简化的写法，Writing bool queries | Elasticsearch.Net and NEST: the .NET clients [7.x] | Elastic

然而这种办法式的调用还是很麻烦，防止不了办法组合

对于个别逻辑查问，通过运算符 (d,!=,>,<) 解决会更简洁

以下示例 ES 版本为 7.x

装置 nuget 包：CRL.Elasticsearch
using CRL;
using CRL.Elasticsearch;

定义数据源

var builder = DBConfigRegister.GetInstance();
            builder.UseElasticsearch();
            builder.RegisterDBAccessBuild(dbLocation =>
            {var dBAccessBuild= new DBAccessBuild(DBType.ES, "http://127.0.0.1:9200/testIndex");
                // 定义连贯设置
                Func<ConnectionSettings, ConnectionSettings> func = (setting) =>
                {setting.DefaultMappingFor<GoodsInfo>(m => m.IndexName("testIndex"));
                    setting.DefaultMappingFor<GoodsInfoChild>(m => m.IndexName("testIndex"));
                    return setting;
                };
                dBAccessBuild.Data = func;
                return dBAccessBuild;
            });

定义查问对象

public class GoodsService:BaseProvider<GoodsInfo>
{}

初始数据

public static void CreateMapping()
        {var service = new GoodsService();
            service.DropTable();
            service.CreateEsIndex();
            var list = new List<GoodsInfo>();
            for (int i = 1; i < 11; i++)
            {list.Add(new GoodsInfo { Id = i.ToString(), DataType = "Goods", Name = "goods" + i, Number = i });
            }
            service.BatchInsert(list);
            var service2 = new GoodsInfoChildService();
            var childs = new List<GoodsInfoChild>();
            childs.Add(new GoodsInfoChild("1", "100", "History") {GroupCode = "001"});
            childs.Add(new GoodsInfoChild("1", "200", "History") {GroupCode = "001"});
            service2.BatchInsert(childs);

        }

按逻辑查问

var service = new GoodsService();
var list = service.QueryList(b => b.DataType == "Goods" && b.Id != "2");
Console.WriteLine($"count should 9 {list.Count == 9}");

对后果进行分组

  public static void testAggregationCount()
    {var service = new GoodsService();
        var query = service.GetLambdaQuery();
        query.Where(b => b.DataType == "Goods");
        query.GroupBy(b => new { b.DataType, b.Name});
        var list = query.ToAggregationCount();
        Console.WriteLine($"count should 2 {list.Count == 2}");
    }

指定查询方法

public static void testMethodAll()
        {var service = new GoodsService();
            var query = service.GetLambdaQuery();
            var ids = new List<Id>();
            ids.Add("1");
            query.Where(b => b.WithIdsQuery(ids));
            query.Where(b => b.Name.WithWildcardQuery("goods*"));
            query.Where(b => b.Name.WithTermQuery("goods"));
            query.Where(b => b.Name.WithMatchQuery("goods", Operator.And));
            query.Where(b => b.Name.WithMatchPhraseQuery("goods"));
            query.Where(b => b.WithMultiMatchQuery(new string[] {"Name", "DataType"}, "goods", Operator.And, TextQueryType.BestFields));
            query.Where(b => b.WithQueryBase(new WildcardQuery
            {
                Field = "Name",
                Value = "goods"
            }));
        }

子查问判断

    public static void testChildQuery()
    {var service = new GoodsService();
        var query = service.GetLambdaQuery().Where(b => b.DataType == "Goods");
        var queryChild = query.CreateQuery<GoodsInfoChild>();
        queryChild.Where(b => b.GroupCode == "001");
        query.HasChild(queryChild);
        var list = query.ToList();
        Console.WriteLine($"count should 1 {list.Count == 1}");
    }

源码示例参考

Data/esTest · hubroxxl/CRL – 码云 – 开源中国 (gitee.com)

扩大 Elasticsearch 客户端简化 ES 查问(.net core/framework)