关于javascript:js原型链继承和class继承

class继承

class People {
    constructor(name, age) {
        this.name = name
        this.age = age
    }
    eat() {
        console.log('I can eat')
    }
}

class Student extends People{
    constructor(name, age, xuehao) {
        super(name, age)
        this.xuehao = xuehao
    }
    read() {
        console.log('I read')
    }
}

const xiaoming = new Student('小明', 16, 8888)
console.log(xiaoming)
xiaoming.eat()  // I can eat
xiaoming.read() // I read

原型链继承

function People(name, age) {
    if (name) this.name = name
    if (age) this.age = age
}

People.prototype.eat = function() {
    console.log('I can Eat')
}

function Student(name, age, xuehao) {
    People.call(this, name, age)
    this.xuehao = xuehao
}

/**
 * 通过将构造函数（Student）的原型（prototype）指向另一个对象（People）的实例，
 * 这是实现原型链继承的最佳技术计划。
 *  */ 

Student.prototype = new People()
/**
 * 然而这样做了之后，Student.prototype.constructor的值就变了，不再是Student了。
 * 所以须要通过Object.defineProperty办法将Student.prototype上的constructor再改成Student。
 * 其实，当Student.prototype = new People()执行后，Student.prototype是People的一个实例，
 * Student.prototype自身没有constructor属性，Student.prototype.constructor其实会去原型链下来找，也就是：
 * Student.prototype.constructor 
 * === Student.prototype.__proto__.constructor 
 * === People.prototype.construcctor === People
 * (实例的隐式原型__proto__等于其构造函数的显式原型prototype，所以有Student.prototype.__proto__ === People.prototype)
 * (而构造函数People的显式原型属性prototype上的constructor指向自身，所以有People.prototype.construcctor === People)
 */
Object.defineProperty(Student.prototype, 'constructor', {
    enumerable: false,
    value: Student,
    writable: true
})

Student.prototype.read2 = function() {
    console.log('I read')
}

const xialuo = new Student('着落', 17, 6666)
console.log(xialuo)
xialuo.eat()  // I can eat
xialuo.read2() // I read